This is really simple, and most people would recommend boost::lexical_cast for this purpose, which is nice if you have boost (apart from the mess of handling the exceptions), but if you just have straight c++ you can still do it without any special utility routines like this: Code (Text): #include <iostream> #include <sstream> int main() { int x = 12345; std::stringstream y; y << "The number is: " << x; std::cout << y.str() << std::endl; return 0; } You can see that the str() method of the std::stringstream object just returns you an std::string. Happy coding
I discovered that std::stringstream can also be used to parse to integer again. Attached is a small program that reads a bunch of integers from the command line, adds them together, and prints the result. Code (C): #include <iostream> #include <sstream> #include <vector> #include <numeric> int main(int argc, char* argv[]) { if (argc <= 1) { std::cout << "Usage: " << argv[0] << " <a> <b> <c> ..." << std::endl; std::cout << "Example: " << argv[0] << " 1 2 3" << std::endl; return 0; } std::vector<int> numbers; for (int i = 1; i < argc; ++i) { int value; std::stringstream ss; ss << argv[I]; /* load the string representation into the stringstream */ ss >> value; /* read it back out as an integer */ if (ss.fail()) { /* detect parser errors */ std::cout << "Error: Argument " << i << " is not an integer!" << std::endl; return 1; } numbers.push_back(value); } /* use the standard library to walk the array and sum the numbers */ int sum = std::accumulate(numbers.begin(), numbers.end(), 0); std::cout << sum << std::endl; return 0; } [/I]
